Object Oriented Programming Practical 16
Question 1
Write a C++ program to declare a class "Book" containing data members book_name, auther_name, and price . Accept this information for one object of the class using pointer to that object.
book.cpp
C
#include<iostream.h>
#include<stdio.h>
#include<conio.h>
class book
{
public:
int price;
char book_name[50],author_name[50];
void accept()
{
cout<<"\nEnter book name: ";
gets(book_name);
cout<<"Enter Book author: ";
gets(author_name);
cout<<"Enter price per copy: ";
cin>>price;
}
void display()
{
cout<<"\nBook name is: "<<book_name<<endl;
cout<<"Book author is: "<<author_name<<endl;
cout<<"Book price is: "<<price<<endl;
}
};
void main()
{
clrscr();
book b,*bptr;
bptr=&b;
bptr->accept();
bptr->display();
getch();
}
Output
Question 2
Write a C++ program to declare a class "Box" having data members height, width and breadth. Accept this information for one object using pointer to that object . Display the area and volume of that object.
box.cpp
C
#include<iostream.h>
#include<conio.h>
class box
{
int height,width,breadth;
public:
void accept()
{
cout<<"\nEnter height of box: ";
cin>>height;
cout<<"\nEnter width of box: ";
cin>>width;
cout<<"\nEnter breadth of box: ";
cin>>breadth;
}
void display()
{
int area=(height*width+width*breadth+breadth*height)*2;
int volume=height*width*breadth;
cout<<"\nArea of box: "<<area;
cout<<"\nVolume of box: "<<volume;
}
};
void main()
{
clrscr();
box b,*bptr;
bptr=&b;
bptr->accept();
bptr->display();
getch();
}
Output
Question 3
Write a C++ program to declare a class birthday having data members day, month, year. Accept this information for five objects using pointer to the array of objects
birthday.cpp
C
#include<iostream.h>
#include<conio.h>
class birthday
{
int day,month,year;
public:
void accept()
{
cout<<"\nEnter day: ";
cin>>day;
cout<<"\nEnter month: ";
cin>>month;
cout<<"\nEnter year: ";
cin>>year;
}
void display()
{
cout<<"\nBirth date is: "<<day<<"/"<<month<<"/"<<year;
}
};
void main()
{
clrscr();
int i;
birthday b[5],*bptr;
bptr=&b[0];
for(i=0;i<5;i++)
{
bptr->accept();
bptr++;
}
bptr=&b[0];
for(i=0;i<5;i++)
{
bptr->display();
bptr++;
}
getch();
}
Output
